12d^2-19d-18=0

Solution for 12d^2-19d-18=0 equation:

12d^2-19d-18=0

a = 12; b = -19; c = -18;
Δ = b2-4ac
Δ = -192-4·12·(-18)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-35}{2*12}=\frac{-16}{24}
=-2/3
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+35}{2*12}=\frac{54}{24}
=2+1/4
$